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48x^2=3
We move all terms to the left:
48x^2-(3)=0
a = 48; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·48·(-3)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*48}=\frac{-24}{96} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*48}=\frac{24}{96} =1/4 $
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